3. Let f be the function given by f(x)=5e3x3. For what positive value of a is the slope of the line tangent to the graph of f at (a,f(a)) equal to 6?
Answer is: option2
Solution:
Slope of line tangent = f′(a)=6
f′(x)=45x2e3x2=6
Now, graph and find the zeroes of
45x2e3x2−6=0
x=0.344