Answer is: option2
\( -28 \)Solution:
\( f(x) = \frac{(g(x))^2}{h(x)} \)
\( f'(x) = \frac{h(x) \cdot (2 \cdot g(x) \cdot g'(x)) - (g(x))^2 \cdot h'(x)}{(h(x))^2} \)
\( f'(-1) = \frac{h(-1) \cdot (2 \cdot g(-1) \cdot g'(-1)) - (g(-1))^2 \cdot h'(-1)}{(h(-1))^2} \)
\( f'(-1) = \frac{(1) \cdot (2 \cdot 2 \cdot (-3)) - (2)^2 \cdot (4)}{(1)^2} \)
\( f'(-1) = -12 - 16 \)
\( f'(-1) = -28 \) Ans