34. A differentiable function \( f \) has the property that \( f(3) = 5 \) and \( f'(3) = 4 \). What is an estimate for \( f(2.8) \) using the linear approximation for \( f \) at \( x = 3 \)?






Answer is: option4

4.2

Solution:

We use linear approximation (tangent line approximation) to estimate \( f(2.8) \). The linear approximation formula is:

\[ f(x) \approx f(a) + f'(a)(x - a) \]

where:

  • \( a = 3 \),
  • \( f(3) = 5 \),
  • \( f'(3) = 4 \),
  • \( x = 2.8 \).

Apply the linear approximation formula

\[ f(2.8) \approx f(3) + f'(3)(2.8 - 3) \]

Substituting the given values:

\[ f(2.8) \approx 5 + 4(2.8 - 3) \]

Simplify the expression

\[ f(2.8) \approx 5 + 4(-0.2) \] \[ f(2.8) \approx 5 - 0.8 \] \[ f(2.8) \approx 4.2 \]

Final Answer - 4.2

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