37. The edge of a cube is increasing at the uniform rate of 0.2 inches per second. At the instant when the total surface area becomes 150 square inches, what is the rate of increase, in cubic inches per second, of the volume of the cube?






Answer is: option3

15 in³/sec

Solution:

We are given a cube where the edge length is increasing at a rate of:

$$\frac{dx}{dt} = 0.2 \text{ in/sec}$$

We need to determine the rate of change of volume, $$\frac{dV}{dt}$$, when the total surface area is 150 square inches.

The surface area of a cube is given by:

$$S = 6x^2$$

Setting $$S = 150$$:

$$6x^2 = 150$$

$$x^2 = 25$$

$$x = 5 \text{ inches}$$

The volume of a cube is:

$$V = x^3$$

Differentiate both sides with respect to $$t$$:

$$\frac{dV}{dt} = 3x^2 \frac{dx}{dt}$$

Substituting $$x = 5$$ and $$\frac{dx}{dt} = 0.2$$:

$$\frac{dV}{dt} = 3(5^2)(0.2)$$

$$= 3(25)(0.2)$$

$$= 15 \text{ in}^3/\text{sec}$$

The correct answer is 15 in³/sec.

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