11. Temperature \( F \) changes according to the differential equation \( \frac{dF}{dt} = kF \), where \( k \) is a constant and \( t \) is measured in minutes. If at time \( t = 0 \), \( F = 180 \), and at time \( t = 16 \), \( F = 120 \), what is the value of \( k \)?






Answer is: option1

-0.025

Solution:

-0.025

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