35. If \( \frac{dy}{dx} = 2y^2 \) and if \( y = -1 \) when \( x = 1 \), then when \( x = 2 \), \( y = \)






Answer is: option2

\( -\frac{1}{3} \)

Solution:

\( -\frac{1}{3} \)

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