AP Calculus AB / Differentiation: Definition and Basic Derivative Rules / Question No. 3

3. \(\lim\limits_{{h \to 0}} \frac{\sqrt[3]{8 + h} - 2}{h} =\)

\(\frac{1}{12}\)

\(\frac{1}{4}\)

\(\frac{\sqrt[3]{2}}{2}\)

\(\sqrt[3]{2}\)

Answer is: option1 - \(\frac{1}{12}\)

Solution:

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