Question | AP Tutor

28. Let \(f\) be the function \(f(x)\) = \( \frac{x}{\ln(x^2)}\) Which of the following conditions explains why \(f(x)\) is not continuous at x =1. (Calculator)

Both \( \lim\limits_{x \to 1} f(x)\) and \(f(1)\) exist, but \( \lim\limits_{x \to 1} f(x) \neq f(1) \).

\( \lim\limits_{x \to 1} f(x)\) exists, but \(f(1)\) does not exist.

Both \( \lim\limits_{x \to 1} f(x)\) and \(f(1)\) exist, but \( \lim\limits_{x \to 1} f(x) = f(1) \).

Neither \( \lim\limits_{x \to 1} f(x)\) nor \(f(1)\) exists.

Answer is: option4

Neither \( \lim\limits_{x \to 1} f(x)\) nor \(f(1)\) exists.

Solution:

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