Answer is: option3
\( 10 \)Solution:
The velocity vector is \[ \mathbf{v}(t)=(6t-4)\mathbf{i}+(2t+2)\mathbf{j}. \]
At the time \( t=2 \), the velocity vector is \[ \mathbf{v}(2)=8\mathbf{i}+6\mathbf{j}=\langle 8,6 \rangle. \]
The speed of the particle is the magnitude (length) of this velocity vector.
\[ \text{Speed}=\sqrt{8^2+6^2}=10 \]
