Answer is:
option2
\(0.337\)
Solution:
The given Maclaurin series is for the function
\[
f(x)=e^{2x}
\]
We use the calculator to find the intersection of the curves
\[
y_1=e^{2x}
\qquad \text{and} \qquad
y_2=2-x^3
\]
The intersection is at
\[
x=0.337
\]
