Answer is: option3 - I and II only
Solution:
I. This is a \(p\)-series with \(p=2\). Convergent
II. This is the alternating harmonic series. Convergent
III. \[
\lim_{n\to\infty} a_n=
\lim_{n\to\infty}\frac{2^n}{n^2}
=\infty
\]
\[
\lim_{n\to\infty} a_n \ne 0
\] Divergent