Answer is:
option1
\( 0.004 \)
Solution:
The Lagrange bound on the error in this 4th degree Taylor polynomial is
\[
\frac{M}{(n+1)!}|x-a|^{\,n+1}
\]
At \( x=2.9,\; a=2,\; n=4,\; M=0.8 \), we have
\[
\frac{0.8}{5!}|2.9-2|^5
=
\frac{0.8}{120}(0.9)^5
\approx 0.004
\]