Answer is: option1
\( 2 \)Solution:
The Lagrange error is
\[ |R_n(x)|=\frac{M}{(n+1)!}|x-a|^{\,n+1} \]
Recall that \( M \) is the upper bound for all values of the \( (n+1) \)st derivative on the given interval \( [a,x] \) in this case.
At \( x=2,\; a=0,\; n=3,\; M=3 \):
\[ |R_3(2)| = \frac{3}{4!}|2-0|^4 = \frac{3\cdot16}{24} = 2 \]
